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p(2) = 1/36p(3) = 2/36p(4) = 3/36p(5) = 4/36p(6) = 5/36p(7) = 6/36p(8) = 5/36p(9) = 4/36p(10) = 3/36p(11) = 2/36p(12) = 1/36So, I will chose Sum=7
Seven, described above already.
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2 comments:
p(2) = 1/36
p(3) = 2/36
p(4) = 3/36
p(5) = 4/36
p(6) = 5/36
p(7) = 6/36
p(8) = 5/36
p(9) = 4/36
p(10) = 3/36
p(11) = 2/36
p(12) = 1/36
So, I will chose Sum=7
Seven, described above already.
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